Back to: Further Mathematics SS1

**MAPPING**

**Definition, Concept, Example, and evaluation.**

**Definition:** This is the rule which assigns an element x in set A to another unique element y in set B.

Set A is called the Domain while set B is the Co-domain

**Image**: This is the unique element in set B produced by an element in set A.

**Range:** This is the collection of all the images of the elements of the domain.

Using the diagram above:

f(w)= g, f(x)= b, f(y)=f, f(z)=a

a, b, f and g are the images of elements a,b,c and d respectively.

Range = {a, b, f, g,}

The rule which associates each element in set A to a unique element in set B is denoted by any of the following notations: f : A → B or f: A→ B

Example 1: Given f(x) = 3x^{2} + 2, find the values of (a) f (4) (b) f (-3) (c) f (-1/2)

**SOLUTION:**

F(x) = 3x^{2}+ 2

(a) F(4), i.e x=4

F(4) = 3(4^{2}) + 2 = 3(16) + 2

= 48 + 2

= 50

(b) F(-3) = 3(-3)^{2}+ 2

= 3(9) +2 = 27 +2

= 29

(c) F(-1/2) = 3(-1/2)^{2}+ 2

= 3(1/4) + 2 = __3 __+ 2

4

=11/4.

Example 2: Determine the domain D of the mapping, g:x→ 2x^{2} – 1, if R= { 1,7,17} is the range and g is defined on D.

**SOLUTION**:

g(x) = 2x^{2}– 1, R = {1,7,17}

To find the domain, when g(x) = 1,

**EVALUATION**

1. Given f(x) = x^{2}+ 4x +3 find the values of.

(a) f(2) (b) f(½) (c) f(-3)

2. Given that f(x) = ax + b and that f(2) = 7 ,f(3) = 12. Find a and b.

**TYPES OF MAPPING**

**One-One mapping:** A mapping is one-one if different elements in the domain have different images in the co-domain. If x_{1}= x_{2 then} f(x_{1}) = f(x_{2})

The mapping is onto and one-one.

NB: In an onto mapping, the range is the same as the co-domain.

**Identity Mapping:** This is a mapping that takes an element onto itself. If f: x→ x is a mapping such that f(x) = x for all x € X.

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