Back to: CHEMISTRY SS1
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In today’s class, we will be talking about writing and balancing chemical equations. Enjoy the class!
WRITING AND BALANCING CHEMICAL EQUATIONS
Chemical equations are a representation of chemical reactions in terms of the symbols and formulae of the elements and compounds involved. In a chemical equation, the reactants are always written on the left-hand side while the products are written on the right-hand side. For instance, if A and B combine together to give C and D, the equation of the reaction is written as:
A + B → C + D
Reactants Products
BALANCING CHEMICAL EQUATIONS
All equations must be balanced in order to comply with the law of conservation of matter. Equations are balanced through the use of coefficients in front of the formula and not by changing the subscript numbers within the formulae of the products.
Example 1: Write a balanced equation for the combustion of ammonia gas in air.
Solution:
Step I: Write the reactants and predict the products
NH3(g) + O2(g) → NO(g) + H2O(g)
Step II: The equation is not balanced. Therefore the equation can be balanced by placing the right coefficient in front of each molecule to balance the number of atoms. Thus, the balanced equation is:
4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g)
Example 2: Write a balanced equation for the combustion of ethane in oxygen.
Solution:
The general formula for the combustion of Alkanes is
CxHy + (x + y/4) O2 → XCO2 + y/2 H2O
The molecular formula for ethane is C2H6, so, x=2 and y=6
Substituting x and y into the formula above gives
C2H6 + (2 + 6/4) O2 →2CO2 + 6/2 H2O
C2H6 + 7/2 O2 →2CO2 + 3H2O
The equation is balanced. However, equations are written with whole-number coefficients. By multiplying the entire equation by 2, we get
2C2H6 + 7O2 →4CO2 + 6H2O
IMPORTANCE OF CHEMICAL EQUATIONS
- It gives us information on the product that can be formed from the combination of two or more reactants in a particular reaction.
- It tells us the physical states of the reactants and products.
- It indicates the direction of the reaction and whether the reaction is reversible.
- It tells us the stoichiometry of the reaction (i.e. the relationship between the amount of reactants and products) in terms of mole ratio of the reactants and products involved.
Consider the table below:
Equation | Mole ratio/ Mass ratio |
2HCl + CaCO3→ CaCl2 + H2O + CO2 | 2 mole of HCl and 1 mole of CaCO3produced 1 mole of CaCl2, 1 mole of H2Oand 1 moles of CO2 |
2HCl + CaCO3 → CaCl2 + H2O + CO2 | 73g of HCl and 100g of CaCO3produced 111g of CaCl2, 18g of H2Oand 44g of CO2 |
GENERAL EVALUATION/REVISION
- Balance the following equations:
(a) KClO3(s) → KCl(s) + O2(g)
(b) ZnCO3(s) + HCl(aq) → ZnCl(aq) + H2O + CO2(g)
- What is the volume in dm3 of 8g of oxygen gas at s.t.p?
- State the use of each of the following apparatuses: triangular pipeclay, beehive shelf, bell jar, fume cupboard, desiccator.
- Outline three differences between physical and chemical changes.
READING ASSIGNMENT
New School Chemistry for Senior Secondary Schools by O.Y. Ababio, pg 36-40
WEEKEND ASSIGNMENT
- A balanced chemical equation obeys which of the laws? A. Law of conservation of matter Law of definite proportion C. Law of multiple proportion D. Boyle’s law
- The numerical coefficients in a balanced equation give the A. number of mole of reactants and products B. molar mass of the reactants and products C. number of reactants only D. mass ratio of the reactants.
- A molecule of neon is A. diatomic B. monoatomic C. triatomic D. polyatomic
- H2SO4 + xKOH → K2SO4 + yH2 The value for x and y in the above equation is A. 1 and 2 B. 2 and 3 C. 2 and 1 D. 4 and2
- The balanced chemical equation for the reaction between hydrochloric acid and sodium hydroxide is NaOH + HCl → NaCl + H2O B. NaCl + HCl → NaOH + H2O
- NaOH + H2SO4 →Na2SO4 + H2O D. H2SO4 + KOH → K2SO4 + H2O
THEORY
- Balance the following equation: H2SO4 + Na2CO3 → Na2SO4 + H2O + CO2
Ca(OH)2 + CO2 → CaCO3 + H2O
2. State two information provided by the equation of a chemical reaction.
In our next class, we will be talking about Identification and Types of Alloys. We hope you enjoyed the class.
Should you have any further question, feel free to ask in the comment section below and trust us to respond as soon as possible.
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I don’t really understand.
Pls, explain more about balancing equation
It was quite interesting