Back to: MATHEMATICS JSS3

*Welcome to JSS3 Third Term!*

*We are eager to have you join us in class!!*

*In today’s class, We will be discussing Geometric Construction. We hope you enjoy the class!*

**Geometric Construction**

Using ruler and compasses

Remember the following when making geometrical constructions.

- Use a hard pencil with a sharp point. This gives thin lines which are more accurate.
- Check that your ruler has a good straight edge. A damaged ruler is useless for construction work.
- Check that your compasses are not too loose. Tighten loose compasses with a small screwdriver.
- All construction lines must be seen. Do not rub out anything which leads to the final result.
- Always take great care, especially when drawing a line through a point.
- Where possible, arrange that the angles of intersection between lines and arcs are about 90
^{0}.

**The perpendicular bisector of a line segment**

The locus of a point which moves so that it is an equal distance from two points, A and B, is the perpendicular bisector of the line joining A and B.

**Perpendicular** means **at right angles to**.

**Bisector** means **cuts in half**.

To construct this locus, you do the following (try this yourself on a piece of paper):

Draw the line segment XY.

Put your compass on X and set it to be over halfway along the line. Draw an arc.

**Constructing a 90**^{0} Angle

^{0}Angle

We can construct a 90º angle either by bisecting a straight angle or using the following steps.

**Step 1:** Draw the arm *PA*.

**Step 2:** Place the point of the compass at *P* and draw an arc that cuts the arm at *Q*.

**Step 3:** Place the point of the compass at *Q* and draw an arc of radius *PQ* that cuts the arc drawn in Step 2 at *R*.

**Step 4:** With the point of the compass at *R*, draw an arc of radius *PQ* to cut the arc drawn in Step 2 at *S*.

**Step 5:** With the point of the compass still at *R*, draw another arc of radius *PQ* near *T* as shown.

**Step 6: **With the point of the compass at *S*, draw an arc of radius *PQ* to cut the arc drawn in step 5 at *T*.

**Step 7:** Join *T* to *P*. The angle *APT* is 90º.

**Constructing a 30**^{0} Angle

^{0}Angle

We know that: ½ of 60^{0 }= 30^{0}

So, to construct an angle of 30º, first, construct a 60º angle and then bisect it. Often, we apply the following steps.

**Step 1:** Draw the arm *PQ*.

**Step 2:** Place the point of the compass at *P* and draw an arc that passes through *Q*.

**Step 3:** Place the point of the compass at *Q* and draw an arc that cuts the arc drawn in Step 2 at *R*.

**Step 4:** With the point of the compass still at *Q*, draw an arc near *T* as shown.

**Step 5:** With the point of the compass at *R*, draw an arc to cut the arc drawn in Step 4 at *T*.

**Step 6:** Join *T* to *P*. The angle *QPT* is 30º.

**Constructing a 60**^{0} Angle

^{0}Angle

We know that the angles in an equilateral triangle are all 60º in size. This suggests that to construct a 60º angle we need to construct an equilateral triangle as described below.

**Step 1:** Draw the arm *PQ*.

**Step 2:** Place the point of the compass at *P* and draw an arc that passes through *Q*.

**Step 3:** Place the point of the compass at *Q* and draw an arc that passes through *P*. Let this arc cut the arc drawn in Step 2 at *R*.

**Step 4:** Join P to R. The angle QPR is 60^{0}, as the ∆PQR is an equilateral triangle

We have come to the end of this class. We do hope you enjoyed the class?

Should you have any further question, feel free to ask in the comment section below and trust us to respond as soon as possible.

In our next class, we will be talking about **Tangent of an Angle.** We are eager to meet you there.

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Joseline JacobI don’t understand the construction of 90°

torywell